CCIE Pursuit Blog

March 31, 2008

Question Of The Day: 31 March, 2008

Topic: IPv6

FastEthernet0/0 is up, line protocol is up
  Hardware is AmdFE, address is cc00.17b4.0000 (bia cc00.17b4.0000)
  Internet address is 100.1.1.1/24

r1(config)#ipv6 unicast-routing
r1(config)#int fa0/0
r1(config-if)#ipv6 address 2001:B00B:1E5:1::/64 eui-64

What will r1’s fao/o IPv6 address be after this configuration is applied?

Click Here For Answer


Yesterday’s Question

 Question Of The Day: 28 March, 2008 

Topic: Route Summarization

You have the following subnets in your network:

132.16.32.0/24
132.16.121.0/24
132.16.34.0/24
132.16.33.0/24
132.16.5.0/24
132.16.181.0/24
132.16.27.0/24
132.16.2.0/24

Write a single summary route that will encompass all of these routes while being as specific as possible.

Answer: 132.16.0.0/16

Since the first two octets (132.16) are the same we need to look at the third octet.  Since we’re writing a single line we can just use the lowest (2) and highest (181) values:

132.16.2.0     10000100 00010000 00000010 00000000
132.16.181.0 10000100 00010000 10110101 00000000

I this case we can see that the first bits that are different the first bits of the 3rd octet.  We can stop right there.  Everything before those bits will be our network address (132.16.0.0) and the rest will be our mask (255.255.0.0)  Our summary will be 132.16.0.0/16.

Route Summarization

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2 Comments »

  1. […] Question Of The Day: 31 March, 2008  […]

    Pingback by Question Of The Day: 01 April, 2008 « CCIE Pursuit — April 1, 2008 @ 9:41 am | Reply

  2. […] Question Of The Day: 01 April, 2008  […]

    Pingback by Question Of The Day: 02 April, 2008 « CCIE Pursuit — April 2, 2008 @ 10:20 am | Reply


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